 Can someone help me with my calculations, I must have made a mistake somewhere but I went over it several times I don’t find it…

The fuel mass flow is regulated to 100kg/h once your over 10500rpm so you have 27.78g of fuel entering the engine every second.

To approximate the fuel, I used octane (C8H18). (I kept the numbers (they get quite small) in the calculator to reduce rounding error)

At 10,500 rpm, you have 27.78g of fuel entering the engine consisting of 6 combustion chambers so about 4.63g of fuel per cylinder and second.

At 10,500 rpm, you have 5,250 power strokes per minute which is equal to 87.5 power strokes per second.

With 4.63g of fuel per cylinder per second and 87.5 power strokes (= number of ignitions) per cylinder per second we get that each cylinder gets 0.053g of fuel per ignition.

The ideal stoichiometric ratio to burn 0.053g of octane is 0.053g octane 0.185g oxygen (O2) according to https://www.chemicalaid.com/tools/reactionstoichiometry.php

The composition of the earths atmosphere is about 21% oxygen (O2) according to wikipedia so we need 0.881g of air to get the 0.185g of oxygen.

A F1 engine cylinder has a displacement of 1.6l = 0.0016m3

The density of air at 1013.25 hPa (abs) and 15°C is 1.225kg/m3 according to wikipedia

Therefore a F1 engine cylinder can contain 0.0016m3 * 1.225kg/m3 = 0.00196kg = 1.96g of air without any boost pressure which would be enough to burn 10 times the current fuel flow limit.

Just in case I didn’t make any mistakes, what are the advantages of boost pressure then?